//反转一个单链表。 
//
// 示例: 
//
// 输入: 1->2->3->4->5->NULL
//输出: 5->4->3->2->1->NULL 
//
// 进阶: 
//你可以迭代或递归地反转链表。你能否用两种方法解决这道题? 
// Related Topics 链表 
// 👍 1518 👎 0

/*
* 206 反转链表
* 2021-02-21 22:36:27
* @author oxygenbytes
*/ 
#include "leetcode.h" 
//leetcode submit region begin(Prohibit modification and deletion)
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* reverseList(ListNode* head) {
        if(!head || !head->next) return head;

        ListNode* pre = nullptr;
        auto cur = head;

        while(cur){
            auto t = cur->next;
            cur->next = pre;
            pre = cur;
            cur = t;
        }

        return pre;
    }
};
//leetcode submit region end(Prohibit modification and deletion)