//反转一个单链表。
//
// 示例:
//
// 输入: 1->2->3->4->5->NULL
//输出: 5->4->3->2->1->NULL
//
// 进阶:
//你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
// Related Topics 链表
// 👍 1518 👎 0
/*
* 206 反转链表
* 2021-02-21 22:36:27
* @author oxygenbytes
*/
#include "leetcode.h"
//leetcode submit region begin(Prohibit modification and deletion)
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* reverseList(ListNode* head) {
if(!head || !head->next) return head;
ListNode* pre = nullptr;
auto cur = head;
while(cur){
auto t = cur->next;
cur->next = pre;
pre = cur;
cur = t;
}
return pre;
}
};
//leetcode submit region end(Prohibit modification and deletion)